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3 years ago

What is the product of 5 and 1/2 times 1/8? I Want see if I’m right.

Mathematics

1 answer:

andreev551 [17]3 years ago

6 0

I got 0.3125 (i don’t know if that’s correct, because the question was hard for me to understand)

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Solve the attachment...

hichkok12 [17]

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

$\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx$

Here 5 is a constant so it can come out . So that,

$\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx$

Now we can write √x as ,

$\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx$

Simplify ,

$\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx$

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

$\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg)$

On simplifying we will get ,

$\longrightarrow \underline{\underline{ I = 2 }}$

8 0

3 years ago

What is the probability of 63?

pogonyaev

63 to 37 odds hope this helps

6 0

3 years ago

A company offers four plans for customers who want to rent DVDs and video games. The cost of the plans can be modeled by a linea

Luba_88 [7]

To solve this, we are going to use the slope formula, and the point slope formula.
Slope formula: $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
where
$m$ is the slope.
$(x_{1},y_{1})$ are the coordinates of the first point.
$(x_{2},y_{2})$ are the coordinates of the first point.
Point-slope formula: $y-y_{1}=m(x-x_{1})$

Plan A. Coordinates of the first point: (1,14) (number of discs, cost). Coordinates of the second point: (2,17). Lets replace those values in our slope formula:
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{17-14}{2-1}$
$m=3$
Now that we have the slope, we can use the point slope formula:
$y-y_{1}=m(x-x_{1})$
$y-14=3(x-1)$
$y-14=3x-3$
$y=3x+11$
Remember that in a linear equation of the form $y=mx+b$ , $m$ is the slope and $b$ is the y-intercept. In our model the y-intercept is the membership fee.
Since $b=11$ in our linear equation, we can conclude that the membership fee is $11

Plan B. Coordinates of the first point (1,12). Coordinates of the second point (2,16).
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{16-12}{2-1}$
$m=4$
$y-y_{1}=m(x-x_{1})$
$y-12=4(x-1)$
$y-12=4x-4$
$y=4x+8$
Membership fee: $8

Plan C. Coordinates of the first point: (1,10). Coordinates of the second point: (2,15).
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{15-10}{2-1}$
$m=5$
$y-y_{1}=m(x-x_{1})$
$y-10=5(x-1)$
$y-10=5x-5$
$y=5x+5$
Membership fee: $5

Part D. Coordinates of the first point: (1,12). Coordinates of the second point (2,21).
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{21-12}{2-1}$
$m=9$
$y-y_{1}=m(x-x_{1})$
$y-12=9(x-1)$
$y-12=9x-9$
$y=9x+3$
Membership fee: $3

We can conclude that the plan that has the smallest one-time membership is <span>Plan D.</span>

6 0

3 years ago

Read 2 more answers

(8a + 3) + (a + 2)

Ierofanga [76]

The answer is 9a+5. All you have to do is combine like terms:)

4 0

3 years ago

What is the solution to <img src="https://tex.z-dn.net/?f=-12%5Cgeq%20x-4" id="TexFormula1" title="-12\geq x-4" alt="-12\geq x-4

Murljashka [212]

....................

4 0

2 years ago