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Savatey [412]
4 years ago
6

Find all complex solutions of x^2-5x+7=0

Mathematics
1 answer:
STALIN [3.7K]4 years ago
3 0

Answer:

x1=5/2+i

x2=5/2-i

Step-by-step explanation:

x^2-5x+7=0

a=1, b=-5, c=7

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-(-5)+sqrt(5^2 - 4*1*7))/2

x1=(5+sqrt(25-28))/2

x1=(5+sqrt(-4))/2

x1=(5+sqrt(4i^2))/2

x1=(5+2i)/2

x1=5/2+i

x2=(-b-sqrt(b^2-4ac))/2a

x2=(5-2i)/2

x2=5/2-iw

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4 years ago
Identity the congruence statement for the triangles below.
GalinKa [24]

<u>Answer:</u>

Triangle HMK≅Triangle ILJ

<u>Explanation:</u>

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According to these criteria, Triangle HMK≅Triangle ILJ



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Source:http://www.1728.org/polygon.htm

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