Answer:
y = -2x^2(x - 3)
Step-by-step explanation:
<em><u>Preliminary Remark</u></em>
If a cubic is tangent to the x axis at 0,0
Then the equation must be related to y = a*x^2(x - h)
<em><u>(3,0)</u></em>
If the cubic goes through the point (3,0), then the equation will become
0 = a*3^2(3 - h)
0 = 9a (3 - h)
0 = 27a - 9ah
from which h = 3
<em><u>From the second point, we get</u></em>
4 = ax^2(x - 3)
4 = a(1)^2(1 - 3)
4 = a(-2)
a = 4 / - 2
a = -2
<em><u>Answer</u></em>
y = -2x^2(x - 3)
5x^2y
5 is the largest number to go in evenly. And the terms are limited to those.
Answer:
I can't seem to solve these but hope this information helps :)
Step-by-step explanation:
Remove any grouping symbol such as brackets and parentheses by multiplying factors.
Use the exponent rule to remove grouping if the terms are containing exponents.
Combine the like terms by addition or subtraction.
Combine the constants.
The first one on the right
If b is greater, then it will be to the right of a
Answer:
a. 
b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)
Step-by-step explanation:
Factor the numerator (Grouping):
Two numbers that multiply to -30 and add to -7 = -3 and 10
![[2x^2 - 10x] + [3x - 15]](https://tex.z-dn.net/?f=%5B2x%5E2%20-%2010x%5D%20%2B%20%5B3x%20-%2015%5D)
Factor the denominator (Difference of Two Squares):
= 
Factored Expression:
(x - 5) can be factored out of top and bottom as a hole-
Variable Restrictions:
Denominator ≠ 0
Vertical asymptote at x = -5 ⇒ x ≠ -5
