50.27yd²
Using the formulasA<span>=</span><span>π</span><span>rto the second power</span>d<span>=</span><span>2</span><span>r</span>Solving forAA=14πd2=14·π·82≈50.26548yd²
Step-by-step explanation:
hope you get idea of graphing the four lines
Answer: Annual Income Is $192000
Step-by-step explanation:
firstly know one month income we divide by 48000 by 3
= 16000
we know one month income 16000
than we for know annual income we multiply by 12
16000×12 =192000
annual income is $192000
Part A.
1. If the parent function 
is shrinked (looks more flattened out and fatter) with coefficient 0<k<1, then its equation is 
2. If the function 
is fatter translated 11 units to the left, then its equation becomes
3. If the function 
is translated 5 units down, then its equation becomes
where 0<k<1.
Answer 1: correct choice is B.
Part B.
1. If the parent function is shrinked (looks more flattened out and fatter) with coefficient 0<k<1, then its equation is
2. If the function is fatter translated 8 units to the right, then its equation becomes
3. If the function 
is translated 1 unit down, then its equation becomes
where 0<k<1.
Answer 2: correct choice is A.
Answer:
The first graph. (an upside down U)
Step-by-step explanation:
The leading coefficient of a polynomial determines the direction of the graph's end behavior.
A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.
A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.
This graph has two evens. Because its negative, only one is possible - the first graph.
The other two graphs are odd with both starting down on the left and point up on the right which is a positive leading coefficient. These are not possible graphs.
The first graph is the solution.
