Answer:
The unit vector u is (-5/√29) i - (2/√29) j
Step-by-step explanation:
* Lets revise the meaning of unit vector
- The unit vector is the vector ÷ the magnitude of the vector
- If the vector w = xi + yj
- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w
- The unit vector u in the direction of w is u = w/IwI
- The unit vector u = (xi + yj)/√(x² + y²)
- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j
* Now lets solve the problem
∵ v = -5i - 2j
∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29
- The unit vector u = v/IvI
∴ u = (-5i - 2j)/√29 ⇒ spilt the terms
∴ u = (-5/√29) i - (2/√29) j
* The unit vector u is (-5/√29) i - (2/√29) j
Answer:
CE= 17.59
Step-by-step explanation:
Arc Length=central angle/ 360 (circumference)
CE= 112/ 360 (2π9)
CE= 17.59
6 : 2/3.....multiply by 3
18 : 2...reduce
9:1 or 9/1
The answer would be:
3 + 3 + 3 + 3...
... If you mean what I'm thinking.
:)
Answer:
Length: 12
Width: 2
Area: 24
Step-by-step explanation:
We first find the points of C and D to find the length.
C: (-4,-5)
D: (2,-3)
The distance is 2
.
Now for the height.
A: (2,9)
D: (2,-3)
The distance is 12.
Area: 2
×12 = 24