Kyla makes a triangular school pennant. The area of the
triangle is 180 square inches. The base of the pennant is z inches long. The
height is 6 inches longer than twice the base length. The base and height can
be solve using the formal A =bh/2
Since b = z and h = 6 + 2z
180 = z(6+2z) /2
B =Z =12 in
H = 30 in
b#~8=+/"1 sep b=.a#~54=|a-10#.|."1 sep a=.10 to 99
17 71
Alternately:
10#.b#~(8=+/"1 b)*.54=|a-10#.|."1 b=.sep a=. 10 to 99
17 71
The answer is 71.
71 - 17 = 54.
a. Recall that
For , we have
By integrating both sides, we get
If , then
so that
We can shift the index to simplify the sum slightly.
b. The power series for can be obtained simply by multiplying both sides of the series above by .
c. We have