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3 years ago

Solve the following inequality. 2 (P + 1) > 7+P

Mathematics

1 answer:

Bond [772]3 years ago

3 0

P > 5

hope this helps

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3 years ago

Solve the equation. Determine whether the equation has one solution, no solution, or

8090 [49]

It has One solution

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3 years ago

Help i need this ill give brainliest

abruzzese [7]

Answer:

0.375

Step-by-step explanation:

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3 years ago

Help plsss I REALLY need help!

Sophie [7]

Answer:

6x^2√x

Step-by-step explanation:

6 times 6 is 36

So you can take 6 out and leave x^5

However x^5 also have a power to square by:

x^4 which can turn into x^2

So we can take x^2 out

So the answer is 6x^2√x

Hope this helps!

8 0

2 years ago

Read 2 more answers

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

4 years ago

Solve the following inequality. 2 (P + 1) > 7+P​

Solve the following inequality. 2 (P + 1) > 7+P