Triangle XYZ is equilateral with vertices located on circle W. Circle W is shown. Line segments W Y, W Z, and W X are radii. Lin
es are drawn to connect the points on the circle to form a triangle. Sides Z X, X Y, and Z Y are congruent. Which measurements are correct? Select two options. mArc X Y = 60° mArc Y Z = 120° mArc Z X = 180° m∠XWZ = 60° m∠YWZ = 120°
2 answers:
Answer:
Step-by-step explanation:
<u><em>The complete question in the attached figure</em></u>
we know that
An equilateral triangle has three equal sides and three equal interior angles (the measure of each interior angle is 60 degrees)
Remember that
The <u><em>inscribed angle</em></u> is half that of the arc it comprises
so
Remember that
<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it
so
----> by central angle
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The answer is 3. I hope this helps :))
Answer: The graph is attached.
Step-by-step explanation:
1. Solve for y, as following:
2. The equation of the line in slope intercept form is:
Where m is the slope and b is the y-intercept.
3. In this case the equation of the line is:
then:
4. Find the x-intercept. Make y=0. Then:
5. Then, plot the line that passes through the points (0,7) and (4.9, 0).
6. The symbol of the inequality is < therefore, the line must be dashed and indicates that the region under the line must be shaded.
Then you obtain the graph attached.
Answer:
a)TRUE
b)FALSE
c)TRUE
d)FALSE
e)TRUE
f)TRUE
g)TRUE
h)FALSE
i)FALSE
j)TRUE
Step-by-step explanation:
a) For every x there is y such that :
TRUE
This statement is true, because for every real number there is a square number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.
b) For every x there is y such that :
FALSE
For example, if x = -1, there is no such real number so that its square equals -1.
c) There is x for every y such that xy = 0
TRUE
If we put x = 0, then for every y it will be xy=0*y=0
d)There are x and y such that
FALSE
There are no such numbers. If we rewrite the equation we obtain an incorrect statement:
e)For every x, if there is y such that xy=1:
TRUE
The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.
f)There is x for every y such that if then xy=1.
TRUE
The statement is equivalent to the statement in e)
g)For every x there is y such that x+y = 1
TRUE
The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x
So, the statement says that for every real umber there is a real number that is equal to 1-that number
h) There are x and y such that
We have to solve this system of equations.
From the first equation it yields x=2-2y and inserting that into the second equation we have:
Which is obviously false statement, so there are no such x and y that satisfy the equations.
FALSE
i)For every x there is y such that
We have to solve this system of equations.
From the first equation it yields and inserting that into the second equation we obtain:
Inserting that back to the first equation we obtain
So, there is an unique solution to this equations:
x=1 and y=1
The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that
j)For every x and y there is a z such that
TRUE
The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.