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vovikov84 [41]
3 years ago
8

Triangle XYZ is equilateral with vertices located on circle W. Circle W is shown. Line segments W Y, W Z, and W X are radii. Lin

es are drawn to connect the points on the circle to form a triangle. Sides Z X, X Y, and Z Y are congruent. Which measurements are correct? Select two options. mArc X Y = 60° mArc Y Z = 120° mArc Z X = 180° m∠XWZ = 60° m∠YWZ = 120°

Mathematics
2 answers:
Ainat [17]3 years ago
6 0

Answer:

The answers are B & E

Step-by-step explanation:

Elis [28]3 years ago
4 0

Answer:

arc\ YZ=120^o

m\angle YWZ=120^o

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

we know that

An equilateral triangle has three equal sides and three equal interior angles (the measure of each interior angle is 60 degrees)

m\angle XYZ=m\angle YZX=m\angle ZXY=60^o

Remember that

The <u><em>inscribed angle</em></u> is half that of the arc it comprises

so

arc\ XY=arc\ YZ=arc\ ZX=2(60^o)=120^o

Remember that

<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it

so

m\angle YWZ=arc\ YZ=120^o ----> by central angle

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Step-by-step explanation:

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0.04 with 4 repeating as a fraction. Not the 04 repeating just the 4 is repeating. What is the answer???
Dmitriy789 [7]

Answer:

2/45

Step-by-step explanation:

0.04... is the same as 0.1 * 0.4... because we are moving it up a decimal place, it's the same as multiplying by ten: we needed to multiply by a tenth to cancel that out. 0.4... is the same as 4/9 and 0.1 is the same as 1/10. We can rewrite the expression above as: (\frac{1}{10} )(\frac{4}{9} ). Multiplying the two fractions results in 4/90 which can be simplified to 2/45.

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Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

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But c=0

\implies -6a=-9

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C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
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