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3 years ago

Write the number in standard notation. 9 x 10^4

Mathematics

2 answers:

bonufazy [111]3 years ago

7 0

10^4 = 10,000

9 x 10,000 = 90,000

navik [9.2K]3 years ago

7 0

Answer:

The number in standard notation is 90 000.

Step-by-step explanation:

The important idea in this exercise is to know the meaning of each operation, and the order we must follow to operate with them.

Recall that the operation with preference is the exponentiation. So, the fisrt calculation must be 10^4, which means the multiplication of 10 by itself four times:

10^4 = 10 x 10 x 10 x 10 = 10000 (ten thousand).

Then, our number is 9 x 10000 = 90000 (ninety thousand)

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8th Grade Functions: Bike Race

Arturiano [62]

Answer:

Juan wins the race

Step-by-step explanation:

The graph is shown in attached image.

The black line is Juan's graph.

The green line is Antonio's graph.

The graph shows the distance (y-axis) with time (x-axis).

The end of the curve(s) means the end of the race. Both curve's ending point in y-axis is 4 miles so the end of the race is 4 miles.

But in x-axis, we see the time:

Juan finishes at 13 minutes

Antonio finishes at 15 minutes

Definitely Juan wins the race

5 0

3 years ago

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Vlada [557]

Answer:

Incorrect

Does not make sense

8 0

3 years ago

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Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph coordinate of E: _

Sholpan [36]

Answer:

Coordinate of E: (-2,3) Coordinate of G: (2.5, 1.5)

Step-by-step explanation:

You first have to find the midpoints of AC and AB.

AC X coordinate:

X1+X2/2

Substitute the x points of AC in

1+(-5)/2=-2

AC Y coordinate:

Y1+Y2/2=3

Substitute the y points of AC in

5+1/2=3

You do the same thing with the AB line. I am pretty sure this works and I hope this helps!

5 0

3 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

3 years ago

-3 + { 1 – 3[20 + 2(-6 – 7)]}

mart [117]

-73 i think it is i might be wrong

7 0

4 years ago