Hey there! I'm happy to help!
The perimeter is all of the sides of a shape added up.
Since all of the sides on a square are the same and we know one side, we just multiply it by four.
2.59(4)=10.36
Therefore, the patio is about 10.56 meters.
I hope that this helps! :D
Answer:
domain={-5,-3,0,2}
range={0,2,4,7}
Step-by-step explanation:
yes
Answer:
Step-by-step explanation:
Applying the Laplace transform:
![\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%2B5%5Cmathcal%7BL%7D%5By%27%5D%2B4%5Cmathcal%7BL%7D%5By%27%5D%3D0)
With the formulas:
![\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%3Ds%5E2%5Cmathcal%7BL%7D%5By%5D-y%280%29s-y%27%280%29)
![\mathcal{L}[y']=s\mathcal{L}[y]-y(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%5D%3Ds%5Cmathcal%7BL%7D%5By%5D-y%280%29)
![\mathcal{L}[x]=L](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bx%5D%3DL)
Solving for 
Apply the inverse Laplace transform with this formula:
![\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs-a%7D%5D%3De%5E%7Bat%7D)
![y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}](https://tex.z-dn.net/?f=y%3D3%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs%2B4%7D%5D%3D3e%5E%7B-4t%7D)
Answer:
BC = 8 and EF = 8.
Step-by-step explanation:
Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).
Set BC and EF equal to each other.
x + 6 = 3x + 2
Subtract x from both sides.
6 = 2x + 2
Subtract 2 from both sides.
4 = 2x.
Divide 2 on both sides.
x = 2.
Substitute 2 for x.
BC = 2 + 6
BC = 8
Since we already know that EF is congruent to BC, EF is also 8.
EC = 3(2) + 2
EC = 6 + 2
EC = 8
Answer:
For the L shaped thing, the area is 224 ft^2
Step-by-step explanation:
18*(18-10) + 10*(18-10) = 224
Just requires some visualizing :) Hope this helps <3
