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Jet001 [13]
3 years ago
5

Find two consecutive odd integers whose sum is 60. Do not type x = in your answer.

Mathematics
1 answer:
Sav [38]3 years ago
8 0

Answer:

Step-by-step explanation:

if 30 +30 = 60 then 29+31=60

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Indicate in standard form the equation of the line through the given points. K(6, 4), L(-6, 4)
azamat

y=4

the values of x changes while the y doesn't so it's y=4

7 0
4 years ago
Read 2 more answers
A summer camp cookout is planned for the campers and their families. there is room for 450 people. each adult costs $7, and each
Yuri [45]

Hence, the required inequality is x+y≤4, 7x+4y≤1150

<h2>What is inequality?</h2>

inequality, In mathematics, a statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

<h3>How to solve?</h3>

Let x be the number of adults and y be the number of campers.

There are rooms for 450 people, so

x+y≤450.

Each adult costs $7, then x adults cost $7x.

Each camper costs $4, then y campers cost $4y.

There is a maximum budget of $1,150, so

7x+4y≤1,150

Hence, you get the system of two inequalities:

         x+y≤4

         7x+4y≤1150

to learn more about inequality: brainly.com/question/16562548

#SPJ4

3 0
2 years ago
If Jonathan paid $32.70 for 5 soccer balls,how much did he pay for each ball ​
Shkiper50 [21]

Answer:

He paid $6.54 for each ball

3 0
3 years ago
Read 2 more answers
PLEAS HELP...FIRST CORRECT ANSWER WILL GET BRAINLIEST....PLEASE ANSWER NOW!!!!
dexar [7]

*a clearer picture containing the graph is shown in the attachment

Answer:

20% of the class earned a D

Step-by-step Explanation:

Step 1: Determine the total number of students represented on the graph:

9 students => D

5 students => C

14 students => B

17 students => A

Total number of students = 45

Step 2: Express each category of students who scored a particular grade as a fraction and as percentage.

9 students => D => \frac{9}{45} = \frac{1}{5} => as percentage, we have \frac{1}{5} * 100 = 20 percent

5 students => C => \frac{5}{45} = \frac{1}{9} => as percentage, we have \frac{1}{9} * 100 = 11.1 percent

14 students => B => \frac{14}{45} => as percentage, we have \frac{14}{45} * 100 = 31.1 percent

17 students => A => \frac{17}{45} => as percentage, we have \frac{17}{45} * 100 = 37.8 percent

Step 3: Check each statement to see if they are true or not based on the calculations above.

Statement 1: "⅕ of the students earned a C."

This is NOT TRUE From our calculation, ⅑ of the students earned a C.

Statement 2: "3% more students earned an A than a B." This is also NOT TRUE.

37.8% earned A, while 31.1% earned a B. Thus, about 6.7% more students earned an A than a B.

Statement 3: "20% of the class earned a D".  This is TRUE.

Check calculation in step 2.

Statement 4: "¼ of the class earned a B". This is NOT TRUE.

¼ is 25% of the class. Those who earned a B account for 31.1% not 25% (¼ of the class).

The correct statement is: "20% of the class earned a D"

7 0
3 years ago
The population of algae in an
mezya [45]

The equation is y = 20(1.40)^x

where x is the number of days and y is the future amount after x days go by

The 1.40 is from the fact that 1+r = 1+0.40 = 1.40, where r is the decimal form of 40%, so r = 0.40

-----------------------------

Plug in x = 7 to get

y = 20(1.40)^x

y = 20(1.40)^7

y = 210.827008

y = 211

We round to the nearest whole number since it doesn't make much sense to have a fractional portion of an algae. After 7 days, there are about <u>211</u> algae.

5 0
3 years ago
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