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3 years ago

13

PLEASE HELP FOR 13 POINTS AND BRAINLIEST! ;)

1 answer:

inessss [21]3 years ago

5 0

Answer:

No because even though you aren't actually picking the exact people yo do and don't wanna survey but your only surveying those who buy hot lunches when in order to get accurate data, you have to survey everyone who bought hot and cold lunches from the school cafeteria.

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Write 2 decimals whose product is 0.16

Nitella [24]

0.4 and 0.4 or 0.8 and 0.2

Hope this helps :)

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3 years ago

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If x=6 and y=−4, evaluate the following expression:10−4xy

Lana71 [14]

Answer:

10-(4×6×-4)

10+96

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Step-by-step explanation:

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2 years ago

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Write the following inequality in slope-intercept form. –12x – 2y ≥ –42 y ≥ –6x – 21 y ≤ –6x – 21 y ≤ –6x + 21 y ≥ –6x + 21

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Step-by-step explanation:

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3 years ago

Solve for x: 2|х - 3 |+1 = 7

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3 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago