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DerKrebs [107]
3 years ago
5

Two trains leave stations 442 miles apart at the same time and travel toward each other. One train travels at 75 miles per hour

while the other travels at 95miles per hour. How long will it take for the two trains to meet?
Do not do any rounding.
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

it will take 2.6 hours or 2 hours and 36 minutes

Step-by-step explanation:

75h+95h=442

solve for h

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How do you answer this question.
Ipatiy [6.2K]
Lets write this out:-

\frac{50}{100} + \frac{30}{100}

To answer this we just need to add the numerators of both fractions because the denominator's are already common multiples. 

\frac{50}{100}+ \frac{30}{100} = \frac{80}{100}

Now lets simplify \frac{80}{100}.

\frac{80/20}{100/20}=  \frac{4}{5}

So, \frac{50}{100}+  \frac{30}{100} = \frac{80}{100}= \frac{4}{5}

Hope I helped ya!! xD
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There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
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Vlad1618 [11]

Answer:

54 balloons in each room

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