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Verdich [7]
3 years ago
7

Round 50.714 to the nearest hundredth ​

Mathematics
2 answers:
defon3 years ago
7 0
The answer would be 50.71
Andrei [34K]3 years ago
4 0
The answer is 50.700.......
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Can some one help me plz??
Hitman42 [59]
The answer is C for this question
5 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

5 0
3 years ago
Help me with my math ASAP!!!!
almond37 [142]

Answer:

f = 78

g = 3.5

Step-by-step explanation:

First we need to find f.

We can use the equation 72 + (f + 30) = 180 to solve for f.

We can then change that equation to 72 + f + 30 = 180, since the Commutative Property of Addition says that you can have any addition in any order.

Now, we can solve the equation.

102 + f = 180\\(102 - 102) + f = 180 - 102\\f = 78

Now that we solved f, we can now solve for g.

Since 25 equals 8g -3, we can solve the equation 8g - 3 = 25.

Here is how you solve it:

8g - 3 = 25\\8g + (-3 + 3) = 25 + 3\\8g = 28\\g = \frac{28}{8}

Since \frac{28}{8} equals 3.5, which is the simplest form, that is the answer.

Hope this helps, and please mark me brainliest! :)

3 0
3 years ago
Need help please thanks.
ANTONII [103]

Answer:

a: 72 degrees

6 0
2 years ago
Find the value of h .
MariettaO [177]

Answer:

xowowo2o2oeoddoxxocckckcll

6 0
3 years ago
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