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dedylja [7]
3 years ago
12

Everything is in the pic

Mathematics
1 answer:
Scrat [10]3 years ago
4 0

Answer:

The correct answer is D) 4/5 and 40/50

Step-by-step explanation:

In order to find this, do the division and find the decimal answer. When they match, they are equivalent.

4/5 = .8

40/50 = .8

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Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
What is the solution to this system of linear equations?2x + y = 13x – y = –6(–1, 3)(1, –1)(2, 3)(5, 0)
worty [1.4K]

\underline{+\left\{\begin{array}{ccc}2x+y=1\\3x-y=-6\end{array}\right}\ \ \ \ |\text{add both sides of equations}\\.\ \ \ \ \ 5x=-5\ \ \ \ |:5\\.\ \ \ \ \ \ x=-1\\\\\text{put the value of x to the first equation}\\\\2(-1)+y=1\\-2+y=1\ \ \ |+2\\y=3\\\\\text{Answer:}\ (-1,\ 3)

5 0
3 years ago
In which quadrant does O lie if the following statements are true:<br> cos 0 &lt; 0 and cscO &gt; 0
Olin [163]

Answer:

2nd quadrant.

Step-by-step explanation:

\text{Given that,}~ \cos \theta < 0~ \text{and}~ \csc \theta > 0.}\\\\\text{So,}~\cos \theta ~ \text{is negative and}~ \csc \theta ~ \text{is positive.}\\\\\text{In Quadrant II, all other ratios are negative except}~ \sin \theta ~ \text{ and}~ \csc \theta.\\\\\text{Hence, the angle lies in the 2nd quadrant.}~

5 0
1 year ago
Help need to do it the equation and the real world problem
melomori [17]

A volleyball uniform costs $13 for the shirt, $11 for pants, and $8 for socks. Write two equivalent expressions for the total cost of 12 uniforms. Then find the cost.  

Write an expression for the cost of 1 uniform, add $13, $11 and $8 .

$13+$11+$8

Write an expression for the cost of 12 uniforms, multiply 12 by the cost of 1 uniform.

12($13+$11+$8)

Simplify using the distributive property.

=12⋅13+12⋅11+12⋅8=156+132+96

Now Add.

=384

So, the total cost of 12 uniforms is $384 .

3 0
3 years ago
A farmer wants to build a new grain silo. The shape of the silo is to be a cylinder with a hemisphere on the top, where the radi
notsponge [240]

Answer:

The radius of the silo should be 16\ ft

Step-by-step explanation:

we know that

The volume of the grain silo is equal to the volume of the cylinder plus the volume of a hemisphere

V=\pi r^{2} h+\frac{4}{6}\pi r^{3}

we have

V=35,500\pi\ ft^{3}

h=4D=8r

substitute the values and solve for r

35,500\pi=\pi r^{2} (8r)+\frac{4}{6}\pi r^{3}

Simplify

35,500=r^{2} (8r)+\frac{4}{6}r^{3}

35,500=8r^{3}+\frac{2}{3}r^{3}

35,500=\frac{26}{3}r^{3}

r^{3}=35,500*(3)/26

r=16\ ft

5 0
3 years ago
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