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Gnesinka [82]
3 years ago
10

at silver gym membrship is 25$ per month and personal training sessions are thirty dollars each.At fit factor membership is 65$

per month and personal training sessions are 20$ each.In one month,how many personal training sessionswould sarah have to buy to make the total cost at the two gyms equal
Mathematics
2 answers:
NARA [144]3 years ago
3 0
25+30x=65+20x
30x=40+20x
10x=40
x=40/10
x=4

x is for the number of sessions

ANSWER: 4 sessions
It will cost 145$ for both gyms after 4 sessions.
Katena32 [7]3 years ago
3 0
Sarah would have to buy a total of 5 (20*3=60) and (30*2=60) for the personal training sessions
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What is 50 x 60 huh who knows
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Consider the following data set. The data were actually collected in pairs, and each row represents a pair.
Anna11 [10]

Answer:

Step-by-step explanation:

Hello!

a.

Using the data sets you have to analyze them as if they are two independent samples.

The hypotheses are:

H₀: μ₁=μ₂

H₁: μ₁≠μ₂

α: 0.05

Assuming that both data sets are from a normal distribution and both population variances, although unknown, are equal, the statistic to use is:

t=\frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

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Sa^2= \frac{9*5.38+9*3.65}{10+10-2} =4.51

Sa= 2.12

t_{H_0}= \frac{(49.69-50.52)-0}{2.12*\sqrt{\frac{1}{10} +\frac{1}{10} } } = -0.875

The p-value for the two-tailed test is:

P(t_{18}≤-0.875) + P(t_{18}≥0.875)= P(t_{18}≤-0.875) + (1 - P(t_{18}≤0.875))= 0.1965 + ( 1 - 0.8035)= 0.393

Since there is no significant level I determined it at 5%, comparing it to the p-value, the hypothesis test is not significant. Meaning that the difference between the population means of both groups is equal to zero.

b.

Considering the given data as a paired sample, you have to determine the variable difference to conduct the test:

Xd: the difference between X₁ and X₂

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Mean X[bar]d= -0.83

Standard deviation Sd= 1.28

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H₀: μd=0

H₁: μd≠0

α: 0.05

t= \frac{X[bar]d-Mud}{\frac{Sd}{\sqrt{n} } } ~~t_{n-1}

t_{H_0}= \frac{-0.83-0}{\frac{1.28}{ \sqrt{10} }} = -2.05

The p-value for the two-tailed test is:

P(t_{9}≤-2.05) + P(t_{9}≥2.05)= P(t_{9}≤-2.05) + (1 - P(t_{9}≤2.05))= 0.0353 + (1 - 0.9647)= 0.0706

Comparing the p-value with the significance level, the hypothesis test is not significant. Meaning that the population mean of the difference between group 1 and group 2 is equal to cero. There is no difference between the two groups.

c.

The value of the statistic in "a" is greater than the value of the statistic obtained in "b". Since there are two samples used an "a" the degrees of freedom of the test are the double as the ones used in "b". The p-value obtained in "b" is around half of the p-value of "a".

The main difference is that in "a" you compared two different samples but in "b" you compared two dependent samples when analyzing paired data the "effect of the individual" is removed from the equation.

I hope this helps!

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Burka [1]

Answer:

(B) An uncontrolled experiment.

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Thus, option B is correct.

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