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3 years ago

HELP ME PLEASE!!!

Mathematics

1 answer:

madam [21]3 years ago

7 0

Answer:

Step-by-step explanation:

<B = <D = 61 (AB parallel with DE)

61 = 2x

x = 30.5

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1) Solve the following equations : a)x/5 + 10 =15 b) 25x + 26 = 101

julia-pushkina [17]

Answer:

1a) 25, 1b) 3, 2a) 14, 2b) 4

Step-by-step explanation:

1a)

x/5 + 10 = 15

Subtract 10 from both sides:

x/5 = 15 - 10

x/5 = 5

Multiply both sides by 5:

x = 5 * 5

x = 25

1b)

25x + 26 = 101

Subtract 26 from both sides:

25x = 101 - 26

25x = 75

Divide both sides by 25:

x = 75/25

x = 3

2a)

Four less than a number is 10.

Let's call the number x. This means:

x - 4 = 10

Now add 4 to both sides:

x = 10 + 4

x = 14

2b)

The product of three and a number equals 12.

Let's call the number x. This means:

3 * x = 12

Now divide both sides by 3:

x = 12/3

x = 4

4 0

2 years ago

Find the center and radius of the circle x2 - 22x + y2 + 20y =4

nasty-shy [4]

Answer:

Step-by-step explanation:

3 0

3 years ago

A farmer has 113 sheep. 47 of them are males. How many more female sheep are there than male sheep?

laiz [17]

Considering the rest of the sheep are females, you just subtract 47 from 113.

6 0

3 years ago

the vertices of triangle PQR are P(-3, 8), Q(-6, -4), and R(1, 1). If you reflect triangle PQR across the x-axis, what will be t

otez555 [7]

Answer:

The coordinates of the vertices of the image will be:

P'=(-3,-8)

Q'=(-6,4)

R'=(1,-1)

Step-by-step explanation:

If you reflect a point P=(x,y) across the x-axis, the coordinates of the image will be P'=(x,-y), then:

P=(-3,8)=(xp,yp)→xp=-3, yp=8→P'=(xp,-yp)→P'=(-3,-8)

Q=(-6,-4)=(xq,yq)→xq=-6, yq=-4→Q'=(xq,-yq)=(-6,-(-4))→Q'=(-6,4)

R=(1,1)=(xr,yr)→xr=1, yr=1→R'=(xr,-yr)→R'=(1,-1)

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3 years ago

X-intercept (__,__) <br> Y-intercept (__,__)

Natasha2012 [34]

Look at the picture.

The x-intercepts are where the graph crosses the x-axis, and the y-intercepts are where the graph crosses the y-axis.

x-intercept (-250, 0)

y-intercept (0, 100)

6 0

3 years ago