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3 years ago

What phrase represents this expression x/3

Mathematics

1 answer:

Anna11 [10]3 years ago

5 0

Answer:

X PARTS OF AN INTEGER DIVIDED INTO 3 PARTS

Step-by-step explanation:

X PARTS OF AN INTEGER DIVIDED INTO 3 PARTS

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3 sin 0 = 3 cos 20<br> what is the solution set?<br>

lutik1710 [3]

Answer:

Step-by-step explanation:

3 sinθ=3 cos 2θ

sin θ=cos 2θ

sinθ=1-2sin² θ

2sin²θ+sin θ-1=0

2sin²θ+2sinθ-sinθ-1=0

2sin θ(sin θ+1)-1(sin θ+1)=0

(sin θ+1)(2 sin θ-1)=0

sin θ=-1=-sin 90=sin (180+90)

θ=270

or sin θ=1/2=sin 30,sin (180-30)

θ=30,150

solution set is {30,150,270}

8 0

3 years ago

The cost of chartering a bus for the great america trip was split evenly by the 20 students planning to go. The day before the t

rewona [7]

Answer:

20c= 30(c-9)

Step-by-step explanation:

The first step in solving a word problem is always to organize the information you have, and put it into equations to solve.

Let c be the cost per student originally.

The cost of the bus has not changed, so the cost/student * the number of students has not changed:

3 0

3 years ago

Which of the following are among the five basic postulates of euclidean geometry? check all that apply

PilotLPTM [1.2K]

The answers are c and d

a straight line segment can be drawn between any two points

any straight line segment can be extended indefinitely

5 0

3 years ago

Read 2 more answers

Find the value of x when 5 - x = 1 2 x + 4 A) -6 B) 2 C) 2 3 D) 3 2

Nitella [24]

Answer:

-1/13

Step-by-step explanation:

5-x= 12x + 4

5-4=12x + x

1 = 13x

-1/13 = x

6 0

3 years ago

Read 2 more answers

In a club there is 13 women and 8 men. A committee of 9 women and 4 men is to be chosen. How many different ways are there to se

sammy [17]

Answer:

The total number of ways to select 9 women and 4 men for the committee is 50,050.

Step-by-step explanation:

The club has 13 female members and 8 male members.

The committee to be formed must have 9 female members and 4 male members.

The possible number of ways to select 9 female from 13 females is:

$n(F)={13\choose 9}=\frac{13!}{9!(13-9)!}=715$

The possible number of ways to select 4 male from 8 males is:

$n(M)={8\choose 4}=\frac{8!}{4!(8-4)!}=70$

Compute the possible total number of ways to select 9 women and 4 men for the committee as follows:

Total number of ways to select 9 women and 4 men = n (F) × n (M)

$=715\times70\\=50050$

Thus, the total number of ways to select 9 women and 4 men for the committee is 50,050.

3 0

3 years ago