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3 years ago

5

The points (2, 1.3), (3, 2.0), (4, 2.2), and (5, 2.8) are modeled by the function y = 0.5x + 0.4. Which graph correctly displays

the residuals of this model?

1 answer:

butalik [34]3 years ago

3 0

I think the answer is C.

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Deon is a software salesperson. His base salary is $1800 and he makes $80 more for every copy of Math is Fun he sells. His total

Vinvika [58]

(a) 34 copies

4520 = 1800 + 80c
2720 = 80c
34 = c

(b) $3,720

P = 1800 + 80(24)
P = 1800 + 1920
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Let me know if you have questions about this

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Two positive integers have a sum of 23 and a product of 126. Find the two numbers.

meriva

Answer:

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Step-by-step explanation:

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The area of the square hole is 8 square centimeters. The volume of a cube shaped block is 64 cubic centimeters. Which edge lengt

damaskus [11]

<u> case a)</u> The area of the square hole is 8 square centimeters

we know that

the area of a square is equal to

$A=b^{2}$

where

b is the length side of the square

in this problem we have

$A=8\ cm^{2}$

<u>Find the length side b</u>

$b^{2} = 8 \\b= \sqrt{8} \ cm\\b= 2\sqrt{2} \ cm$

<u>the answer Part a) is</u>

the length side of the square is $2\sqrt{2} \ cm$

Part b) The volume of a cube shaped block is 64 cubic centimeters

we know that

the volume of a cube is equal to

$V=b^{3}$

where

b is the length side of the cube

in this problem we have

$V=64\ cm^{3}$

<u>Find the length side b</u>

$b^{3} = 64 \\b= \sqrt[3]{64} \\b= 4\ cm$

therefore

<u>the answer Part b) is</u>

the length side of the cube is $4\ cm$

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3 years ago

Through: (4, 3), perp. to y = 2x + 3 <br><br>write the equation please

GrogVix [38]

Because it’s perpendicular, the slope must be -1/2, which is the opposite of 2. You can put the points into y-3=-1/2(x-4) and simplify if need be.

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3 years ago

Reflection Over Parallel Lines Please complete the attached reflection. Thanks!

Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

4 0

3 years ago