Answer:
Step-by-step explanation:
A). g(x) = x² - 9x + 14
Since coefficient of highest degree term (x²) is positive, parabola will open upwards.
For any parabola opening upwards,
Right end behavior,
y → ∞ as x → ∞
B). Let the equation of the linear function is,
f(x) = mx + b
Where m = slope of the function
b = y-intercept
From the graph attached,
Slope 'm' =
m = -3
b = -1
Therefore, function 'f' will be,
f(x) = (-3)x - 1
f(x) = -3x - 1
g(x) = x² - 9x + 14
= x² - 7x - 2x + 14
= x(x - 7) - 2(x - 7)
= (x - 2)(x - 7)
If h(x) = f(x)g(x)
h(x) = -(3x + 1)(x -2)(x - 7)
For h(x) ≥ 0
-(3x + 1)(x - 2)(x - 7) ≥ 0
Or 2 ≤ x ≤ 7
Therefore, for 2 ≤ x ≤ 7, h(x) ≥ 0
C). If k(x) =
k(x) =
k(x) = -(3x + 1)(x - 7)
For k(x) = -56
-(3x + 1)(x - 7) = -56
3x² -20x - 7 = 56
3x² - 20x - 63 = 0
3x² - 27x + 7x - 63 = 0
3x(x - 9) + 7(x - 9) = 0
(3x + 7)(x - 9) = 0
Answer:
Let a be the first term.
The sum is a1−r=33.25.
The second term is ar=7.98, so a=7.98/r.
Putting these together, 7.98/r(1−r)=33.25 or r(1−r)=0.24=0.6×0.4.
If the answer doesn't jump out at you from there, you could solve for r with the quadratic formula.
Step-by-step explanation:
I Hope It's Helpful :)
Answer:
17
Step-by-step explanation:
Answer:
Shanti is 10 units away from the middle school
Step-by-step explanation:
Plot the given points on an x-y coordinate set of axes as shown in the attached image.
Notice that Shanti's location is given with an orange point, and that the middle school location with a green point.
Since they both have the same x-coordinate value (-5), it is very simple to calculate the distance in between them by simply counting the number of units that separate them vertically.
If you do such you get your answer: 10 units.