Answer:
1. = 3xy + x - 2y - 4
2. = d^2(2c^3-8c^2d+3d^2)
Step-by-step explanation:
= 9x^2y^2 + 3x^2y - 6xy^2 - 12xy/3xy
First factor the top equation ….
= 3xy(3xy + x - 2y - 4)/3xy
If the top and the bottom both carry 3xy, you can cancel out both of them leaving you with ….
= 3xy + x - 2y - 4
= -16c^6d^6 + 64c^5d^7 - 24c^3d^8/-8c^3d^4
First factor the top equation ....
= -8c^3d^6(2c^3-8c^2d+3d^2)/-8c^3d^4
If the top and the bottom both carry -8c^3 you can cancel out both of them leaving you with ….
= <u>d^6</u>(2c^3-8c^2d+3d^2)/d^4
Apply the exponent rule with d^6 ....
= <u>d^4</u><u>d^2</u>(2c^3-8c^2d+3d^2)/d^4
cancel out d^4 ....
= d^2(2c^3-8c^2d+3d^2)
when solving for y
y = -7x/3-6
so y does not vary directly with x
the answer is no
Answer: 67 love!
Step-by-step explanation: look at the picture below love!
The frequency of getting an even number is 48%
Answer:
f
(
x
)
=
3
x
3
−
5
x
2
−
47
x
−
15
Explanation:
If the zero is c, the factor is (x-c).
So for zeros of
−
3
,
−
1
3
,
5
, the factors are
(
x
+
3
)
(
x
+
1
3
)
(
x
−
5
)
Let's take a look at the factor
(
x
+
1
3
)
. Using the factor in this form will not result in integer coefficients because
1
3
is not an integer.
Move the
3
in front of the x and leave the
1
in place:
(
3
x
+
1
)
.
When set equal to zero and solved, both
(
x
+
1
3
)
=
0
and
(
3
x
+
1
)
=
0
result in
x
=
−
1
3
.
f
(
x
)
=
(
x
+
3
)
(
3
x
+
1
)
(
x
−
5
)
Multiply the first two factors.
f
(
x
)
=
(
3
x
2
+
10
x
+
3
)
(
x
−
5
)
Multiply/distribute again.
f
(
x
)
=
3
x
3
+
10
x
2
+
3
x
−
15
x
2
−
50
x
−
15
Combine like terms.
f
(
x
)
=
3
x
3
−
5
x
2
−
47
x
−
15
