We are asked in the problem to determine the inverse of the relation y = 3x + 12. first step is to express the equation in terms of y, that is y -12 = 3x, then exchange the places of x and y, that is x - 12 = 3y. This is the final answer
<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
N + 7 = 12
Step-by-step explanation:
When you have a number minus a negative number, it's the same as addition.
ΔADC ≅ ΔBCD (SAS congruency)
∠AED ≅ ∠BEC (opposite angles)
ΔAED ≅ ΔBEC (ASA congruency)
Therefore DE <span>≅ CE (corresponding sides of the two congruent triangles AED and BEC)</span>
