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3 years ago

Please I need help on this one

Mathematics

1 answer:

lesantik [10]3 years ago

3 0

Answer:

2520

Step-by-step explanation:

18×24=432

432÷2=216

216×35=7560

7560÷3=2520

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Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph

Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

$y=-\frac{7}{4}x+4$

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

$y_1=mx+b$

And the second one, that is perpedicular to the one above:

$y_2=nx+c$

The slope of the second one is the negative inverse of the first one:

$n=-\frac{1}{m}$

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

$\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}$

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

$y-y_1=m(x-x_1)$

replace with the coordinates of the point and the slope and calculate:

$\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}$

Subtract 7 to both sides of the equation to write it in slope-intercept form:

$\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}$

Now you can graph both lines

8 0

1 year ago

Please help me solve this

In-s [12.5K]

Step-by-step explanation:

Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.

For example if x=-4

$- ( - 4) + 5 = 9$

If x=-2

$- ( - 2) + 5 = 7$

If x=0

$0 + 5 = 5$

$- 2 + 5 = 3$

$- 4 + 5 = 1$

So our point should be

-4,9

-2,7

0,5

-2,3

-4,1.

The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.

(9,7,5,3,1)

5 0

2 years ago

clara is playing a game where you score -8 points each time you guess the correct answer. the goal is to get the lowest score. t

Lina20 [59]

Answer:

272

Step-by-step explanation:

-8--280=272

7 0

3 years ago

Which dimensions can create only one unique triangle?

daser333 [38]

The correct answer is B.

Good luck!!!

5 0

3 years ago

Read 2 more answers

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago