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Vladimir [108]
3 years ago
10

Please help will mark brainliest

Mathematics
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

LMN is rectangle in L so LMN= 180° ; ML=66°;N=?  N= 180°- 66°=114=114/2= 57° so N=57°

Step-by-step explanation:

When the angle at the top is close to 0 °, the two of the base get less than 180 °, or less than 90 ° for each. If the angle at the top is 60 °, the other two are: 180 - 60 = 120 °, and each is: 120/2 = 60 °.

beks73 [17]3 years ago
7 0

Answer:

m\angle N=57^{\circ}

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares LM\cong LN, the remaining unknown angles are equal (m\angle N=m\angle M). The sum of the interior angles of a triangle always add up to 180^{\circ}$.

Therefore:

m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$} .

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Answer:

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Step-by-step explanation:

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Then, you put the two values in a fraction - 18/36

and simplify, to get you 1/2.

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Check whether the function yequalsStartFraction cosine 2 x Over x EndFraction is a solution of x y prime plus yequalsnegative 2
Jobisdone [24]

The question is:

Check whether the function:

y = [cos(2x)]/x

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xy' + y = -2sin(2x)

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Answer:

To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.

Let us do that.

y = [cos(2x)]/x

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Now,

xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x

= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)

= -2sin(2x)

Which is the right hand side of the differential equation.

Hence, y is a solution to the differential equation.

6 0
3 years ago
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AveGali [126]
<h2><u>Answer</u><u> </u><u>:</u></h2>

x + 23 = -22

x = ?

x = -22 - 23

x = - ( 22 + 23 )

x = -45

x = -45 ✔️

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2 years ago
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