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2 years ago

11

The method of writing very large or small numbers as a product of a number equal to or greater than 1 and less than 10 by a powe

r of 10 is known as
a0.

1 answer:

slavikrds [6]2 years ago

4 0

It is known as scientific notation

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For every quarter he spends, Reggie receives 50 food pebbles to feed the fish. Reggie has thrown 350 food pebbles into the fish

deff fn [24]

Answer:

7 quarters are spent for throwing 350 food pebbles in pond.

Step-by-step explanation:

Given:

Reggie receives 50 food pebbles for every quarter he spends.

Number of food pebbles he has = 350

Let the number of quarters spent for 350 pebbles be 'x'.

Now, using proportion and cross multiplication method, we can find 'x'.

<u><em>1 quarter is equivalent to 50 pebbles thrown in pond.</em></u>

<u><em>So, 'x' quarters is equivalent to 350 pebbles thrown in pond.</em></u>

$\frac{1}{50}=\frac{x}{350}\\\\Cross\ multiplying\\\\50x=350\\\\x=\frac{350}{50}\\\\x=7$

So, 7 quarters are spent for throwing 350 food pebbles in pond.

6 0

2 years ago

Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.

Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the following condition must be followed:

Either (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

for the equation ax² + bx + c = 0

thus,

the roots are

$x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}$

or

$x = \frac{6\pm\sqrt{36-12}}{2}$

or

$x = \frac{6+\sqrt{24}}{2}$ and, x = $x = \frac{6-\sqrt{24}}{2}$

or

$x = \frac{6+2\sqrt{6}}{2}$ and, x = $x = \frac{6-2\sqrt{6}}{2}$

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}$

or

$x = \frac{4\pm\sqrt{16+56}}{4}$

or

$x = \frac{4+\sqrt{72}}{4}$ and, x = $x = \frac{4-\sqrt{72}}{4}$

or

$x = \frac{4+\sqrt{2^2\times3^2\times2}}{2}$ and, x = $x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}$

or

$x = \frac{4+(2\times3)\sqrt{2}}{2}$ and, x = $x = \frac{4-(2\times3)\sqrt{2}}{4}$

or

$x = \frac{2+3\sqrt{2}}{2}$ and, $x = \frac{2-(3)\sqrt{2}}{2}$

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

7 0

2 years ago

Need help ASAP AND SHOW WORK PLEASE !! 40 points

Vinvika [58]

Area = 20
perimeter = 21

5 0

2 years ago

Read 2 more answers

O panglica a fost taiata, prin 5 taieturi , in bucati cu lungimea de 35 cm . Cati metri masura panglica?

Amiraneli [1.4K]

35×5=175 (metri măsoară pamblica)

3 0

3 years ago

What is the value of x?

Alina [70]

Answer:

-1

Step-by-step explanation:

4 0

2 years ago