Which expression is equivalent to 5c + 3c?

Follow the directions to solve the system of equations by elimination. 8x + 7y=39 4x – 14y = -68

harina [27]

Step-by-step explanation:

Hey there!

Here;

The equations are;

$8x + 7y = 39.......(i)$

$4x - 14y = - 68..........(ii)$

Multiplying equation (i) by 2.

16x + 14y = 78

4x - 14y = -68

20x = 10

$x = \frac{10}{20}$

x = 1/2.

Putting value of 'x' in equation (i).

$8 \times \frac{1}{2} + 7y = 39$

$4 + 7y = 39$

$7y = 3 9 - 4$

$y = \frac{35}{7}$

Therefore the value of y is 5.

Check:

Put value of x and y in equation (i).

8x + 7y = 39

$8 \times \frac{1}{2} + 7 \times 5 = 39$

$4 + 35 = 39$

$39 = 39$

(True).

Therefore, the solution is ; (1/2,5).

Hope it helps...

8 0

4 years ago

I need help on this problem! g(h+2/3)=1 for h

Tju [1.3M]

Answer:

$g(h + \frac{2}{3} ) = 1 \\ \\ gh + \frac{2}{3} g = 1 \\ \\ gh = 1 - \frac{2}{3} g \\ \\ h = (1 - \frac{2}{3} g ) \div g \\ \\ h = (1 - \frac{2}{3} g ) \times \frac{1}{g} \\ \\ h = \frac{1}{g} - \frac{2}{3}$

I hope I helped you^_^

7 0

3 years ago

Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed

Ad libitum [116K]

Answer: The answer is $7\dfrac{7}{8}$ ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

$b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.$