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Llana [10]
3 years ago
10

Which expression is equivalent to 5c + 3c?

Mathematics
1 answer:
topjm [15]3 years ago
6 0

the correct Number is 8c

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Follow the directions to solve the system of equations by elimination. 8x + 7y=39 4x – 14y = -68​
harina [27]

Step-by-step explanation:

Hey there!

Here;

The equations are;

8x + 7y = 39.......(i)

4x - 14y =  - 68..........(ii)

Multiplying equation (i) by 2.

16x + 14y = 78

<u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>4</u><u>y</u><u> </u><u> </u><u> </u><u>=</u><u> </u><u>-68</u>

20x = 10

x =  \frac{10}{20}

x = 1/2.

Putting value of 'x' in equation (i).

8 \times  \frac{1}{2}  + 7y =  39

4 + 7y = 39

7y = 3 9 - 4

y =  \frac{35}{7}

Therefore the value of y is 5.

<u>Check</u><u>:</u>

<u>Put</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>and</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>(</u><u>i</u><u>)</u><u>.</u>

8x + 7y = 39

8 \times  \frac{1}{2}  + 7 \times 5 = 39

4 + 35 = 39

39 = 39

(True).

<u>Therefore</u><u>, </u><u>the</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>;</u><u> </u><u>(</u><u>1</u><u>/</u><u>2</u><u>,</u><u>5</u><u>)</u><u>.</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
4 years ago
I need help on this problem! <br><br> g(h+2/3)=1 for h
Tju [1.3M]

Answer:

g(h +  \frac{2}{3} ) = 1 \\  \\ gh +  \frac{2}{3} g = 1 \\  \\ gh = 1 -  \frac{2}{3} g \\  \\  h = (1 -  \frac{2}{3} g )  \div g \\  \\ h = (1 -  \frac{2}{3} g ) \times   \frac{1}{g}  \\  \\ h =  \frac{1}{g}  -  \frac{2}{3}

I hope I helped you^_^

7 0
3 years ago
Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed
Ad libitum [116K]

Answer:  The answer is 7\dfrac{7}{8} ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.

We can see that

b_1-b_0=b_2-b_1=\dfrac{11}{8}.

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.

Thus, the weight of the puupy after 3 weeks will be

b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.

5 0
3 years ago
Read 2 more answers
The following is a square, solve for x
QveST [7]

Answer:

6

Step-by-step explanation:

Multiply 7x+3 by 2. When you get 14x+6, set equal to 90 and solve for x.

7 0
3 years ago
Which equation represents the inverse
STatiana [176]

I'd say A, since there, all the operations are the opposite from the original function.

Hope it helped,

BioTeacher101

4 0
3 years ago
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