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2 years ago

What is the measure of the missing angle?

Mathematics

2 answers:

Hoochie [10]2 years ago

8 0

The answer would be D because triangles add up to 180 degrees and the two angles together only add up to 140, so the missing angles would be 40 degrees

sergiy2304 [10]2 years ago

4 0

D. 40 degrees

This is the answer because 70+70=140
There is 180 degrees in a Triangle. So you must subtract 140 from 180.
180-140=40.

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Find the inverse for: f(x) = x + 1/2

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Answer:

f-1(x)=x-1/2

Step-by-step explanation:

Switch x and y and solve for y

x=y+1/2

y=x-1/2

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The base radius of a cone is 8 mm, and it’s volume is 320mm. What is its height ?

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Suppose you toss a 6-sided die 40 times, with 14 tosses landing on the five. What percentage of the tosses would be fives?

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$\dfrac{14}{40}\cdot100\%=35\%$

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2 years ago

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PLSSS HELP!!! 40 pts!!!!

quester [9]

Answer:

∠1=135°

∠2=45°

∠3=45°

∠4=135°

∠5=135°

∠6=45°

∠7=45°

∠8=135°

Step-by-step explanation:

→∠1=∠4[Being vertically opposite angles]

→∠4=135°

→∠1=∠5[Corresponding angles]

→∠5=135°

→∠5=∠8[Being vertically opposite angles]

→∠8=135°

→∠1+∠2=180°[Sum of linear pair]

→∠2=180°-135°

→∠2=45°

→∠2=∠3[Being vertically opposite angles]

→∠3=45°

→∠3=∠6[Alternate angles]

→∠6=45°

→∠6=∠7[Being vertically opposite angles]

→∠7=45°

3 0

2 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

podryga [215]

Answer with explanation:

$\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}$

Average Height of tallest Building in San Francisco

$=\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8$

Average Height of tallest Building in Los Angeles

$=\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9$

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco

=233.9-197.8

=36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

|260-197.8|=62.2

|237-197.8|=39.2

|212-197.8|=14.2

|197 -197.8|= 0.8

|184 -197.8|=13.8

|183-197.8|=14.8

|183-197.8|= 14.8

|175-197.8|=22.8

|174-197.8|=23.8

|173 -197.8|=24.8

Average of these numbers

$=\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12$

Mean absolute deviation=23.12

5 0

2 years ago