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AysviL [449]
3 years ago
8

Help need answer ASAP due in 10 minutes

Mathematics
1 answer:
enyata [817]3 years ago
4 0

Answer:

1) about 9 or 8.7

2) 4

3) about 5 or 4.5

4) 2

5) about 4 or 4.4

6) 2

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B) John returns from holiday with these notes.
ivolga24 [154]

Answer:

£290.70

Step-by-step explanation:

Number of notes of $50 = 5

Total value = 50 × 5 = $250

Number of notes of $20 = 2

Total value = 20 × 2 = $40

Number of notes of $10 = 7

Total value = 10 × 7 = $70

Number of notes of $5 = 3

Total value = 5 × 3 = $15

Total value of all notes with John = 250 + 40 + 70 + 15

                                                        = $375

Since, $1.29 = £1

Therefore, $1 = £\frac{1}{1.29}

Therefore, $375 = £ \frac{375}{1.29}

                           = £290.70  

4 0
3 years ago
Help me with differentation and integration please!!
Marina86 [1]

Answer:

See below

Step-by-step explanation:

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

Recall

\dfrac{d}{dx}\tan x=\sec^2

Using the chain rule

\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}

such that u = \tan x

we can get a general formulation for

y = \tan^n x

Considering the power rule

\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}

we have

\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x

therefore,

\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x

Now, once

\sec^2 x - 1= \tan^2x

we have

3\tan^2x \sec^2x =  3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x

Hence, we showed

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

================================================

For the integration,

$\int \sec^4 x\, dx $

considering the previous part, we will use the identity

\boxed{\sec^2 x - 1= \tan^2x}

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx $

Considering u = \tan x

and then du=\sec^2x\ dx

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx  = \dfrac{\tan^3 x}{3}+\tan x + C }$

6 0
2 years ago
How do we write 33 1/3 % as a fraction?
djyliett [7]

Answer:

As a fraction it must be 1/3

3 0
3 years ago
You take out a bagel and place it in the toaster for 5 minutes the toaster uses 1050 watts/hour
Veronika [31]
If the power consumption is linear, then the toaster consumed 1050*(5/60)=87.5 watts.
3 0
3 years ago
Locate and label each point on the number line. Use the diagram to answer the questions. lives one block north of the pizza shop
nata0808 [166]

Answer: dog human

Step-by-step explanation: dog eat dog food

3 0
2 years ago
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