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elixir [45]
3 years ago
14

-13x=90-2y -6x=48-2y

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0

While it's pretty obvious to most of us that


-13x=90-2y

-6x=48-2y


is a system of linear equations, it'd be well to include that info plus the instructions "solve this system of linear equations."


Subtract the 2nd equation from the first:


-13x=90-2y

+6x=-48+2y

-----------------------

-7x = 42. Then x = -42/7, or x = 6.


Now subst. 6 for x in either one of the given equations. Suppose we use the 2nd equation:


-6x=48-2y


Then -6(6)=48-2y, or -36 = 48 - 2y, or 2y = 48+ 36 = 84. Then y = 42.


The solution is (6, 42).

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15 players for a softball team show up for a game: (a) How many ways are there to choose 10 players to take the field? 3003 (b)
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Answer:

(a) 3003 ways

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(c) 3002 ways

Step-by-step explanation:

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Solving (a) Ways of selecting 10 players.

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r=10

Using:

^nC_r = \frac{n!}{(n-r)!r!}

We have:

^{15}C_{10} = \frac{15!}{(15-10)!10!}

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Simplify

^{15}C_{10} = \frac{15*14*13*12*11*10!}{5!10!}

^{15}C_{10} = \frac{15*14*13*12*11}{5!}

^{15}C_{10} = \frac{15*14*13*12*11}{5*4*3*2*1}

^{15}C_{10} = \frac{360360}{120}

^{15}C_{10} = 3003

Solving (b) Ways of assigning positions to 10 players.

This implies permutation.

So, we have:

r=10

Using:

^nP_r = \frac{n!}{(n-r)!}

We have:

^{15}P_{10} = \frac{15!}{(15-10)!}

^{15}P_{10} = \frac{15!}{5!}

Solve each factorial

^{15}P_{10} = \frac{1307674368000}{120}

^{15}P_{10} = 10897286400

Solving (c) Ways of choosing at least 1 woman

We have:

Men = 10

Women = 5

Ways of selecting 10 players is: (a) 3003 ways

Since the number of men are 10, there is 1 way of selecting 10 men (i.e. selection without women)

Using complement rule:

At least 1 woman = Total - No woman

At\ least\ 1\ woman = 3003 - 1

At\ least\ 1\ woman = 3002

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