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pishuonlain [190]
3 years ago
10

What is the solution to this system of equations?

Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

C. x = 5, y = 2

Step-by-step explanation:

Simply plug in each given term in the answer choices, evaluate, then find out which two will make the system of equations authentic, or genuine.

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A lottery ticket has a grand prize of $48.9 million. The probability of winning the grand prize is .000000047. Determine the exp
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Is this a gcse question??
7 0
3 years ago
your classmate tells you the details of the great deal he got on his mortgage: 30- year 3.5% fixed rate with a 10% down payment.
DIA [1.3K]

Answer:

$13,600

Step-by-step explanation:

If he puts a down payment of 10% on $136,000

Then is should be $13,600

4 0
3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
Zigmanuir [339]
-3x-6y=17

-6y=3x+17

y=-x/2-17/6 so the slope of the line is -1/2

For another line to be perpendicular to this one the product of their slopes must equal -1

(-1/2)m=-1, m=2  so the perpendicular line will have a slope of 2...

y=2x+b, using point (6,3) we can solve for b...

3=2(6)+b

3=12+b

b=-9 so

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4 0
3 years ago
The endpoint coordinates of AB are A(2, -10) & B(12, 5). Find the coordinates of the point that is 2/5 from A to B.
sergey [27]
<h3>Answer: \large \boldsymbol {\sf 2\sqrt{13} \approx7,2}</h3>

Step-by-step explanation:

  • Find the distance between points A and B by the formula:

  • \large  \boldsymbol {\sf D=\sqrt{(x_1-x_2)^2+(y_1+y_2)^2} }

  • \large \boldsymbol{}  \sf D=\sqrt{(2-12)^2+(-10-5)^2} =\sqrt{100+225} =\boldsymbol {\sqrt{325}=5\sqrt{13}  }  

  • By the condition we are told to find 2/5 the distance between points A and B

  • \sf \large \boldsymbol {} \dfrac{2}{5} \cdot D=5\sqrt{13}  \cdot \dfrac{2}{5} =\boxed{\sf 2\sqrt{13}}

  • We can also find the distance between them through the  Pythagorean theorem we will complete a right triangle
  • AB²=AC²+BC²
  • AB=√AC²+BC²
  • Where AC=10  ; BC=15  
  • AB=\boldsymbol {\sf \sqrt{15^2+10^2}=\sqrt{325}=5\sqrt{13}   }
  • Then 2/5* AB=2\sqrt{13}

3 0
3 years ago
Read 2 more answers
Which of the following functions have a vertical asymptote for values of theta such that cos theta = 1? Select two answers.
Sergio039 [100]
The sine is zero at such angles, so
.. y = csc(θ)
.. y = cot(θ)
both have vertical asymptotes there.

The last 2 selections.
7 0
3 years ago
Read 2 more answers
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