All categories

3 years ago

HELP ASAP PLEASE!!

Mathematics

1 answer:

aleksklad [387]3 years ago

4 0

Answer:

1+y= 2

y = 2 - 1

y = 1

y=-12+3

y = -9

Step-by-step explanation:

first you rewrite the question, then you group like terns.

After that you do the needful operation example; if the question is asking you to add or subtract or divide or multiply.

later, you write your final answer down.

hope it helps .

Please mark brainliest

You might be interested in

What is tan(B)? B 5 13 5 12 ? tan(B) = = Enter

SOVA2 [1]

Answer:

tan B = 12/5

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side/ adj side

tan B = 12/5

3 0

2 years ago

In the figure below, find the value of cose:

MariettaO [177]

Answer:

Step-by-step explanation:

cosΘ = $\frac{adjacent}{hypotenuse}$ = $\frac{x}{r}$

4 0

2 years ago

The route for one day of a charity bike ride covers 50 miles. Individual participants ride this distance at different average sp

nlexa [21]

How many cubic feet are in a carton measuring 6 feet, 8 inches by 3 yards by 4.5 inches?

7 0

3 years ago

59:26 What is the length of the hypotenuse, x, if (20, 21, x) is a Pythagorean triple? 22 29 41 42

Vikki [24]

If the legs are length a and b and hyptonuse is c then
a²+b²=c²

so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x

4 0

3 years ago

Read 2 more answers

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

3 years ago

Read 2 more answers