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True [87]
3 years ago
5

Please please help me

Mathematics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

<h2>           A = 189 cm²</h2>

Step-by-step explanation:

The area of a parallelogram is equal to the product of the length of its <u>side and the height</u> of the parallelogram <u>perpendicular to that side</u>.

H = 9 cm

S = 21 cm

A = S•H = 21 cm • 9 cm = 189 cm²

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Answer:

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Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

\Omega=\{WW,WN,NW,NN\}

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

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Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

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Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

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Thus the option WN has the probability

\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}

Now for the second option NW. The initial probability to pick a non-white counter is

\displaystyle \frac{6}{11}

The probability to pick a white counter is

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Thus the option NW has the probability

\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}

The total probability of event A is the sum of both

\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}

\boxed{\displaystyle P(A)=\frac{6}{11}}

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