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Anton [14]
3 years ago
12

Which expression can you simplify by combining like terms?

Mathematics
2 answers:
almond37 [142]3 years ago
8 0
12b^2+4ab-3ba-6
=12b^2+ab-6
pashok25 [27]3 years ago
5 0
You can reduce the first one by combining the ab and the ba term
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The quadrilateral is a rhombus.<br> If EF = 13 and DF = 18, find EH to the nearest tenth.
-Dominant- [34]

Answer:

EH = 9.4

Step-by-step explanation:

A rhombus is a quadrilateral with equal length of sides.

Given that,  EF = 13 and DF = 18

⇒ DH = HF = \frac{18}{2}

             = 9

The property that the diagonals of a rhombus are at right angle to each other.

Thus, applying the Pythagoras theorem, we have;

/hyp/^{2} = /adj1/^{2} + /adj2/^{2}

(EF)^{2} = (EH)^{2} + (HF)^{2}

(13)^{2} = (EH)^{2} + (9)^{2}

169 =  (EH)^{2} + 81

(EH)^{2} = 169 - 81

           = 88

EH = \sqrt{88}

      = 9.381

The length EH is 9.4

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3 years ago
The heights, in inches, of the 11 basketball players on a
yarga [219]
ANSWER: 6 99

for height. inches. of the 11 basket

8 0
3 years ago
Read 2 more answers
Find expressions for the possible dimensions of a rectangular prism with a volume of 3m? + 7m2 +2m.
SashulF [63]

Answer:

  B.  m, (3m +1), and (m +2)

Step-by-step explanation:

The product of the constants in the binomials must be +2 in order for those binomials to be factors of the volume expression. That is only the case for ...

  B.  m, (3m +1), and (m +2)

7 0
2 years ago
The Carousel at Carowinds has 4 rings of horses. Fred is riding on the inner ring, which has a radius of 7 feet. Juan is riding
nikdorinn [45]

Answer:

Juan travel 31.4 feet farther than Fred in one rotation.

Step-by-step explanation:

In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:

s=\theta \cdot r (Eq. 1)

Where:

r - Radius, measured in feet.

\theta - Angular arch, measured in radians.

s - Change in linear position, measured in feet.

If both makes one rotation in the carousel, we obtain the change in linear position of each player:

Fred (r = 7\,ft, \theta = 2\pi)

s= 2\pi\cdot (7\,ft)

s = (3.14)\cdot (7\,ft)

s = 21.98\,ft

Juan (r = 17\,ft, \theta = 2\pi)

s= 2\pi\cdot (17\,ft)

s = (3.14)\cdot (17\,ft)

s = 53.38\,ft

And the difference between both travelled distances is:

\Delta s = 53.38\,ft-21.98\,ft

\Delta s = 31.4\,ft

Juan travel 31.4 feet farther than Fred in one rotation.

4 0
3 years ago
Amber earns $150 a week plus $10 for each tree she sells.
Charra [1.4K]

Answer:

Step-by-step explanation:

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3 years ago
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