<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
Formula: Heat = mass * specific heat * ΔT
Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C
=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J
2. If a refrigerator is a heat pump that follows the first law of
thermodynamics, how much heat was removed from food inside of the
refrigerator if it released 492J of energy to the room? Joules
The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room
=> Answer = 492 J
3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules
Formula: heat = mass * specific heat * ΔT
specific heat of water = 4186 J / Kg °C
heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
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The rate of change is the same as the slope.
Let's find the slope of function 1 using the Rise Over Run rule.
The rise is 2 and run is 1. So your rate of change is 2/1 or 2 for function 1
Function 2 is a y = mx + b equation, the slope is usually "m" or before the x
y = 1/2x + 7
1/2 is your rate of change for function 2
5/7 +1/3
find the common denominator for both of the fractions
common denominator is 21
mutiply by 3 for 5/7
(5)(3)/(7/(3)= 15/21
mutiply by 7 for 1/3
(1)(7)/(3)(7)= 7/21
15/21+7/21
add the numerators
15+7= 22
denominator stays the same -21
Answer:
22/21 or 1 1/21
1500 x .16 = $240 in comission
365 - 240 = $125 in hourly wages
125 / 20 = $6.25/hr
Answer:
I thinks it's the third one
