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sveticcg [70]
3 years ago
5

A placebo is a substance that should elicit no positive response in an experimental subject.

Mathematics
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

  A)  True

Step-by-step explanation:

In an experiment that has the purpose of testing the efficacy of a procedure or drug, comparison is made against the efficacy of a placebo, a procedure or drug that is <em>intended to have no effect whatever</em>.

__

Famously, a placebo is often found to be nearly as effective (or even more effective) than the procedure or drug on trial. This effect is known as "the placebo effect."

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a number is divided by 3 and the result is added to 1. the new result is doubled to give the final result 80. whats the number
Gnesinka [82]
78, because you have to do the inverse operation so 80/2= 40 then 40-1= 39 and 39*3 = 78
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4 years ago
I need help solving these equations....
Harlamova29_29 [7]
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3 years ago
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Vesna [10]

(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =

= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}

= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}

= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}

= 2^{-16-12+28} \times 5^{10-8}

= 2^{0} \times 5^{2}

= 1 \times 25

= 25

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3 years ago
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fiasKO [112]

Answer:

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Step-by-step explanation:

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3 years ago
Is -2 a solution to 4x^(3)-x^(2)+16x-4
sergiy2304 [10]

Answer:

Not a solution

Step-by-step explanation:

In order for x=-2 to be a solution, the result after substituting must be 0:

4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0

4(-8)-4-32-4\stackrel{?}{=}0

-32-40\stackrel{?}{=}0

-72\neq0

Therefore, x=-2 is not a solution to 4x^3-x^2+16x-4

3 0
3 years ago
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