What’s the ratio for tan B?
1 answer:
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Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
Answer:
x = -4
Step-by-step explanation:
16 = 4*4 = 4²
64 = 4 * 4* 4 = 4³
As bases are same, compare exponents
6x + 48 = -6x
Subtract 48 from both sides
6x = -6x - 48
Add '6x' to both sides
6x + 6x = -48
12x = -48
Divide both sides by 12
x = -48/12
x = -4