P= 2.5m + 35 (replace p with 115)
115= 2.5m + 35 (subract 35 from each side)
115 - 35 = 2.5m
80 = 2.5m (divide 2.5 from each side)
80/2.5= 2.5m/2.5
32 = m
The price of the materials is $32
<u>Answer:</u>
The correct answer option is B. 2 = 3x + 10x^2
<u>Step-by-step explanation:</u>
We are to determine whether which of the given equations in the answer options can be solved using the following expression:

Here,
and
.
These requirements are fulfilled by the equation 4 which is:

Rearranging it to get:

Substituting these values of
in the quadratic formula:


Answer:
2. YWX
Step-by-step explanation:
<T and <Y are congruent
<W and <W are congruent
<Z and <X are congruent
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e.
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587