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sdas [7]
3 years ago
13

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are

the coordinates of B' after the translation? (1, 6) (–3, 6) (0, 0) (3, 1).
Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

The coordinates of point B' are (-3, 6).

<h2>Given that</h2>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

<h3>We have to determine</h3>

What are the coordinates of B' after the translation?

<h3>According to the question</h3>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

\rm B(0, \ 5) = B (0-3, \ 5+1) = B(-3, \ 6)

Therefore, the coordinates of point B' are (-3, 6).

To know more about Transformation click the link given below.

brainly.com/question/26297555

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