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marshall27 [118]
3 years ago
13

What is 2+2. Please help

Mathematics
2 answers:
jonny [76]3 years ago
4 0

Answer:

4

Step-by-step explanation:

2 added by another 2, results in 4

umka2103 [35]3 years ago
3 0

Answer:

4

Step-by-step explanation:

2 add 2 is 4............

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Step-by-step explanation:

is there any drawing beside it ? pls ..the first X is equal to the second x ?

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Describe the graph represented by the equation r=5/(3+2 sin theta).
Yuki888 [10]
We have the following equation:

r= \frac{5}{3+2sin(\theta)}

If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:

1. Center of the ellipse: 

The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
C(0, -2)

2. Length of major axis:

The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>

6 \ units

3. Length of minor axis:

The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:

4 \ units

4. Foci:

Let's find c as follows:

c=\sqrt{a^{2}-b^{2}}=\sqrt{3^{2}-2^{2}}=\sqrt{5}

Then the foci are:

f_{1}=(0, \sqrt{5}-2)

f_{2}=(0, -\sqrt{5}-2)

8 0
3 years ago
What was the speed on each part of the trip
Tcecarenko [31]
They went slower time by time
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6 0
3 years ago
Select the correct answer from each drop-down menu.
Oksi-84 [34.3K]

Answer:

we \: have \: ohms \: law \: h =  {i}^{2} rt \\  \frac{h}{t}  =  {i}^{2} rt \div t = p \\  p =  {i}^{2} r....(1) \\ we \: have \: v = ir \\ i =  \frac{v}{r} .....(2) \\ put \: (2) \: in \: (1) \\ then \: p =  { (\frac{v}{r}) }^{2} r \\ p =  \frac{ {v}^{2} }{r}  \\ v =  \sqrt{pr}  =  {(pr)}^{ \frac{1}{2} }  \\ 2) \\ here \: r = 32 \: and \: p = .5 \\ then \: v =  \sqrt{32 \times .5}  \\  =  \sqrt{16}  = 4volt \\ thank \: you

6 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Points A and B
Maurinko [17]

Answer:

The answer for the question is 11 and 12 I just got a test back and it was correct

Step-by-step explanation:

5 0
3 years ago
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