<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
Answer:
Step-by-step explanation:
I am sorry but please give detailed question
Answer:
B. The shape can be broken into a rectangular prism and a rectangular pyramid.
C. The formula for the volume of this figure is V = B h + one-third B h.
D. The volume of the container is 2,760 centimeters cubed.
Step-by-step explanation:
I did the edge test.
Division property of equality because you divide the same by the same number on both sides of the equation
Step-by-step explanation:
X = adding by 6 and Y you add my 1
