A.
continuious means they both approach the same number as they approach 1
basically, find the vallues of q in terms of p for which both of them equal 1
so
1+2p(1-1)+(1-1)^2=1 (this simplifies to 1=1 so don't mess with the p)
q(1)+p=1, q+p=1, q=1-p
the value of q that will make it continous at x=1 is 1-p
B. find the values of p and q such that their derivitives are equal at x=1
first one's derivitive:
2px+2x-2, at x=1, 2p+2-2=2p
2nd one's derivitive:
q
so
2p=q
from the value in part a
q=1-p
2p=1-p
add p to both sides
3p=1
divide by 3
p=1/3
q=1-1/3
q=2/3
the function is
1+(2/3)(x-1)+(x-1)^2 for x≤1 and
(2/3)x+(1/3) for x>1
C. take the derivitive twice to get
0 and
0
both same deriritive
find if they have the same value
well, 0=0
yes
A. q=1-p
B. p=1/3, q=2/3
C. yes, both have value of 0 and change of slope is 0
Answer:
P_1st year = P0 x (1 + r/n) = P0 x (1 + r/n)^1
P_2nd year = P0 x (1 + r/n) (1 + r/n) = P0 x (1 + r/n)^2
...
P_n year = P0 x (1 + r/n)^n
Hope this helps!
:)
Answer:
Step-by-step explanation:
D because there in to parenthesis so you're correct.
Answer:
216π cubic centimeters
Step-by-step explanation:
Answer:
a=2
Step-by-step explanation:
u=3b-2(2) or u=3b-4
