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lisabon 2012 [21]
3 years ago
12

Find the x-and y- intercepts of 2x+9y=-4

Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0
X-intercept:(-2,0)
Y-intercept:(0, -4/9)
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Solve the following system of equations by substitution<br> 2x – 3y = -1<br> y = x - 1
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Answer:

(4, 3)

Step-by-step explanation:

Plug in x - 1 where y is. The equation will turn in 2x - 3(x - 1) = -1. Distribute, and you'll have 2x -3x + 3 = -1. Combine like terms (2x and -3x) and you'll have -x + 3 = -1. Subtract 3 from both sides, and you'll have -x = -4. Divide by -x (or -1) on both sides, and you'll have x = 4. Since y = x - 1, y = 3, since 4 - 1 = 3. Sorry if this sounds repetitive btw. Good luck :D

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Which two functions are inverses of each other? A. f(x) = x, g(x) = –x B. f(x) = 2x, g(x) = -1/2x C. f(x) = 4x, g(x) = 1/4x D. f
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B. f(x)=2x, g(x)= -1/2x. Hope this helps. :-)
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I need help plz..No spam​
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Explain how to identify the terms of 3y - 4 - 5y
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Well the answer is -2y-4 but the different terms in this problem are 4 and 5y and 3y where 5y and 3y are like terms
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<img src="https://tex.z-dn.net/?f=4%20%5Ctimes%208%20%5E%7B2x%20%2B%201%3F%7D%20%20%3D%2032%20%5E%7Bx%20%2B%202%7D%20" id="TexFo
svet-max [94.6K]

Answer:

x = 5

Step-by-step explanation:

<u>__________________________________________________________</u>

<u>FACTS TO KNOW BEFORE SOLVING</u> :-

  • a^x \times a^y = a^{x+y}
  • In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : a^x = a^y  ⇒  x = y  [∵ Bases are equal on both the sides]

<u>__________________________________________________________</u>

4 \times 8^{2x+1} = 32^{x+2}

Lets express it in terms of 2.

=> 2^2 \times 2^{3 (2x+1)} = 2^{5(x+2)}

=> 2^2 \times 2^{6x+3} = 2^{5x+10}

=> 2^{2 + 6x+3} = 2^{5x+10}

=> 2^{6x+5} = 2^{5x+10}

Here the bases on both the sides are equal. Hence ,

=> 6x + 5 = 5x + 10

=> 6x - 5x = 10 - 5

=> x = 5

6 0
3 years ago
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