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ladessa [460]
4 years ago
13

Simplify 42 ⋅ 48. The 2 and 8 are exponents

Mathematics
2 answers:
FromTheMoon [43]4 years ago
5 0
4 to the 10. When multiplying with same base, add exponents.
Scilla [17]4 years ago
4 0
<span><span>THE ANSWER IS: 1048576</span></span>

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Donovan fed his dog for 5 weeks and used 12 lbs of dog food, at the same rate. How much dog food will he use in 8 weeks?
Anna [14]

Answer:

19.2 lbs of dog food in 5 weeks

Step-by-step explanation:

12 divided by 5 is 2.4

So that means each week the dog consumes 2.4 lbs of food each week.

If we want to see how much he eats in 8 weeks, we'd multiply 2.4 by 8, giving us 19.2

8 0
3 years ago
Profit is always calculated as revenue minus expenses. If a company's expenses were $10 million, write an equation that expresse
Usimov [2.4K]

Answer:

c. P=R-10; 35 million

Step-by-step explanation:

P=R-10, just read what the text says, namely profit = revenue - expenses

P=25, 25=R-10 <=> R=35

3 0
3 years ago
Read 2 more answers
One leg of a right angle has a length of 3m. The other sides have lengths
snow_lady [41]
I don’t understand what the question is
3 0
3 years ago
PLEASE HELP!
Nadya [2.5K]

Answer: no solution or zero solutions.

Step-by-step explanation:

8 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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