set f(x) equal to y
y = 19/ x^3
swap x and y
x = 19/y^3
make y the subject
xy^3 = 19
y^3 = 19/x
![y = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
then just replace y with f^-1(x)
![f(x) = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
hope this helped! have a good day ~ •lipika•
4x+20=5y
Divide 5 on both sides
so your answer would be
4/5x+4=y
x+15=3y
Divide 3 on both sides
so your answer would be
3x+5=y
Answer:
Youre answer would be y
≥
7
13
y≥7/13
Step-by-step explanation:
Move all terms not containing
y
y
to the right side of the inequality.
13
y
≥
7
13y≥7
Divide each term by
13
13
and simplify.
Divide each term in
13
y
≥
7
13y≥7
by
13
13
.
13
y
13
≥
7
13
13y13≥713
Reduce the expression by cancelling the common factors.
y
≥
7
13
y≥713
A reciprocal just flips the fraction
1. 
2.
3. Before it is flipped it is
but it turns into 
Hope this helps!
Answer:
C. horizontal line that is 33.8 units
Step-by-step explanation:
We assume your equation should be ...

The largest denominator in this standard-form equation of an ellipse is under the y-term, so the major axis is vertical. The directrix will be a horizontal line.
The distance from the center to the directrix is always longer than the semi-major axis, so will be more than √169 = 13. This only leaves choice C.
__
If "c" is the center-to-focus distance, it will be the root of the difference of the denominators in the equation:
c = √(169 -144) = 5
For semi-major axis "a", the distance from the center to the directrix is ...
a²/c = (13²)/5 = 33.8 . . . . . matches choice C