Answer:
The statement is true about whether A and B are independent eventa is fourth option:
A and B are not independent events because P(A/B)=0.375 and P(A)=0.25
Step-by-step explanation:
Let A be the event that the person rides the bus to school, then:
P(A)=75/300
P(A)=0.25
Let B be the event that the person has 3 or more siblings, then:
P(B)=24/300
P(B)=0.25
P(A/B)=9/24
P(A/B)=0.375
Like P(A/B)=0.375 is different to P(A)=0.25 the events are not independent
Answer. Fourth option:
A and B are not independent events because P(A/B)=0.375 and P(A)=0.25
Answer:
x = 2
Step-by-step explanation:
X² = 3x - 7 = 0
X² = 3x = 7
(x + 1) (x + 2) = 7
(x + 1) + x = 7 - 2
x + x = 7 - 3
2x = 4
x = 4/2
x = 2
Y would equal to -5. hope this helps
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
ok but what's the question? u gave us info but what's the question
