Substitute answers in, a = 3 and b = 2.
(3^2 - 2^2)/(3+2)
= (9-4)/5
= 5/5
= 1
Answer:
126807 people
Step-by-step explanation:
Given;
P= Poe^ht
Where;
P= population at time t
Po= population at the beginning
h= growth constant
t= time
1998- 2008 is ten years.
110429= 100,000e^10h
1.1 = e^10h
ln(1.1) = lne^10h
0.095 = 10h
h= 0.0095
In 2023, t = 25 years
P= 100,000e^(0.0095 × 25)
P= 126807 people
Answer:
M/6 = G/5
Step-by-step explanation:
We are given a relation between the numbers of students in two different groups. That relation can be used to write an equation.
<h3>Groups who bought M&Ms</h3>
If we consider M&M buyers to be 6 in a group, then the number of those groups is ...
M/6
<h3>Groups who bought gum</h3>
Similarly, the number of groups who bought gum will be ...
G/5
where there are 5 gum-buyers in each group.
<h3>Equation</h3>
The problem statement tells us that for each group of one kind, there is a matching group of the other kind. That is, the numbers of groups are equal:
M/6 = G/5
If a box has a square base its volume will be:
V=hb^2 where h is the height...
h=V/b^2 we are told that V=125 so
h=125/b^2 now for the surface area, which consists of the two bases for a total of 2b^2. It will also have four sides with a total area of 4(bh)=4bh so
A=2b^2+4bh, using h found above in this gives us:
A=2b^2+4b(V/b^2)
A=2b^2+4V/b
A=(2b^3+4V)/b, then taking the derivatives we can find the velocity of the area function.
dA/db=(6b^3-2b^3-4V)/b^2
dA/db=(4b^3-4V)/b^2
dA/db=0 when 4b^3-4V=0
b^3=V
b=V^(1/3), since V=125
b=5in, and since h=V/b^2
h=125/25=5in
So the dimensions that will minimize the amount of material used to enclose a volume of 125in^2 is a 5in cube.
h=b=5in
