The area of the two triangular bases is (total base area) = 2×(1/2)bh = bh = (10 m)(6 m) = 10·6 m² = 60 m²
The area of the three rectangles making up the remaining faces of the prism is (total lateral area) = length×base + length×height + length×hypotenuse = length×(base + height + hypotenuse) = (16 m)(10 m + 6 m + 11.6 m) = (16 m)(27.6 m) = 16·27.6 m² = 441.6 m²
Then the surface area of the prism is the sum of these surface area = total base area + total lateral area = 60 m² + 441.6² = 501.6 m² When rounded to the nearest whole number, this is A) 502 m²
