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3 years ago

How to find surface area of a right triangular prism to the nearest whole number?

1 answer:

5 0

The area of the two triangular bases is
(total base area) = 2×(1/2)bh
= bh
= (10 m)(6 m) = 10·6 m² = 60 m²

The area of the three rectangles making up the remaining faces of the prism is
(total lateral area) = length×base + length×height + length×hypotenuse
= length×(base + height + hypotenuse)
= (16 m)(10 m + 6 m + 11.6 m)
= (16 m)(27.6 m) = 16·27.6 m² = 441.6 m²

Then the surface area of the prism is the sum of these
surface area = total base area + total lateral area
= 60 m² + 441.6² = 501.6 m²
When rounded to the nearest whole number, this is
A) 502 m²

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3 years ago

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3 years ago

Read 2 more answers

Drag each tile to the correct box.

ch4aika [34]

Answer:

1. 50 cm

2. 550 mm

3. 5000 mm

4. 5000 cm

5. 5000 m

Step-by-step explanation:

We can convert all the measures in same unit to arrange them one by one.

5000 cm:

As there are 10 millimeters in 1 cm,

5000 cm = 5000*10mm

=> 50000 mm

5000 meters:

As there are 100 cms in one meter

5000 m = 5000*100 cm

=> 500000 cm

Now to convert in millimeter

500000*10= 5000000 mm

50 cm:

50*10 = 500 mm

Then there is 550 mm and 5000 mm

So, the order from least to greatest is:

1. 500 mm which is equivalent of 50 cm

2. 550 mm

3. 5000 mm

4. 50000 mm which was equivalent of 5000 cm

5. 5000000 mm which was equivalent of 5000 m ..

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3 years ago

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe

enot [183]

Answer:

$n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2$ , in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that $\pi = 0.16$

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which $M = 0.03$ . So