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zysi [14]
2 years ago
8

How is 81^1/4 is 3?

Mathematics
1 answer:
e-lub [12.9K]2 years ago
6 0

Answer:

\sqrt[4]{81}  =  {( {3}^{4}) }^{ \frac{1}{4} }

Step-by-step explanation:

it's obvious that 3·3·3·3=81

or you can do the prime factorization of 81

You might be interested in
Which of the following values does not satisfy the inequality -2x - 6 is less than or equal to 1
Vsevolod [243]

Answer:

X ≥ 3.5

Step-by-step explanation:

-2x-6≤1

+6 +6

-2x≤7

-2x/2 7/2

x ≥ 3.5

5 0
3 years ago
Once upon a time, there was a former whose family raised pigs and chickens. One morning, the farmer's wife looked into the barny
Fed [463]

Using a system of equations, it is found that:

  • There are 8 chickens in the yard.
  • There are 16 pigs in the yard.

-----------------------------------------

This question is solved using a system of equations. I am going to say that:

  • x is the number of chickens.
  • y is the number of pigs.

-----------------------------------------

  • A chicken has 1 head, as do a pig.
  • There are 24 heads.

Thus:

x + y = 24 \rightarrow y = 24 - x

-----------------------------------------

  • A chicken has 2 feet.
  • A pig has 4 feet.
  • In total, there are 80 feet.

Thus:

2x + 4y = 80

-----------------------------------------

Number of chicken:

Since y = 24 - x

2x + 4y = 80

2x + 4(24 - x) = 80

2x + 96 - 4x = 80

2x = 16

x = \frac{16}{2}

x = 8

There are 8 chickens in the yard.

-----------------------------------------

Number of pigs:

y = 24 - x = 24 - 8 = 16

There are 16 pigs in the yard.

A similar problem is given at brainly.com/question/24104709

8 0
3 years ago
How many outliers are there in this data set 1, 4, 6, 9, 12, 13, 13, 17, 19
Katarina [22]
Just find the average and whatever is more than like say 5 away is an out lier
8 0
3 years ago
PLS HELP ASAP IM HAVING A STROKE UNDERSTANDING THIS
stich3 [128]

Answer:

Question number 5

Answer-parallelogram

5 0
2 years ago
Read 2 more answers
In recent years, only 79% of the fruit sold at Fred's Fruit stand has been any good. Fred recently started buying fruit from new
Juli2301 [7.4K]

Answer:

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

Step-by-step explanation:

79% of the fruit sold at Fred's Fruit stand has been any good. Test if there has been an increase.

At the null hypothesis, we test if there has been no increase, that is, the proportion is still of 79%, so:

H_0: p = 0.79

At the alternative hypothesis, we test if there has been an increase, that is, more than 79% being good, so:

H_1: p > 0.79

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.79 is tested at the null hypothesis:

This means that \mu = 0.79, \sigma = \sqrt{0.79*0.21}

In a random sample if 475 pieces, 85 were bad.

So 475 - 85 = 390 were good, and:

n = 475, X = \frac{390}{475} = 0.8211

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8211 - 0.79}{\frac{\sqrt{0.79*0.21}}{\sqrt{475}}}

z = 1.66

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.8211, which is 1 subtracted by the p-value of Z = 1.66.

Looking at the z-table, z = 1.66 has a p-value of 0.9515.

1 - 0.9515 = 0.0485

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

5 0
3 years ago
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