Answer:
(-7, -12)
Step-by-step explanation:
4x-3y=8
5x-2y=-11
Is there any of the like terms can be added and the result will be 0? No, so we have to multiple one OR both of the equations to make that one number do that.
(I will try to remove the y like terms so i will multiple both of them by the opposite so both of the ys will be 6)
2(4x-3y=8)
-3(5x-2y=-11)
8x-6y=16
-15x+6y=33
(now the easy part… cancel the 6s and add the equations)
8x+(-15x)=-7x
16+33=49
-7x=49
(divide 49 by -7)
x=-7
Replace x in any of the equations and you’ll get the y value.
4x-3y=8
4(-7)-3y=8
-28-3y=8
-3y=36
y=12
Threfore, there is one solution which is….. (-7,-12)
There is no picture or anything but it’s ok .
Answer: 6/24 ????????????
Step-by-step explanation:
Let x = the first number
x+1 = the second number
The sum of our two numbers is therefore: x + (x+1)
When you subtract 13 from the above you get 18 left over.
So our equation is:
x + (x+1) - 13 = 18
Now we can just solve for x:
x + (x+1) = 31
2x + 1 = 31
2x = 30
x = 15
So our first number is 15 and our second number must be 16.
Answer:
The distance between X and Z is approximately 95.99 km
Step-by-step explanation:
- Given, X, Y and Z are three points on a map. Y is 85km and on a bearing of 190° from X. Z is on a bearing of 140°, from Y. Z is due south of X.
(For Diagram Please Find in Attachment)
The distance of Y from X = 85 km
The bearing of Y from X = 190°
The bearing of Z from Y = 140°
The bearing of Z from X = 180°
Now,
∠YZX = 180° - (130° + 10°) = 40°
- Therefore, Apply the sine rule here, we get
(85 km)/sin(40°) = XZ/(sin(130°))
XZ = sin(130°) × (85 km)/sin(30°) ≈ 95.99 km
The distance between X and Z ≈ 95.99 km
