Which is a equation of the line that has the slope of - 4and passes through the point (- 2, 5)?
2 answers:
Answer:
The equation of the line
y = -4x - 3
Step-by-step explanation:
The equation of the line
y = mx + c
y = intercept point y
m = slope of the line
x = intercept point x
c = intercept of the line
Given
Slope = -4
Point = ( -2 , 5)
x = -2
y = 5
Insert the values into the equation
y = mx + c
5 = -4(-2) + c
5 = 8 + c
5 - 8 = c
c = 5 - 8
c = -3
Insert c into the equation of a line
y = -4x - 3
The equation of the line is
y = -4x - 3
Answer:
y = - 4x - 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 4, thus
y = - 4x + c ← is the partial equation
To find c substitute (- 2, 5 ) into the partial equation
5 = 8 + c ⇒ c = 5 - 8 = - 3
y = - 4x - 3 ← equation of line
You might be interested in
P(a | b) = p(a ∩ b)/p(b) . . . . . a definition worth remembering
0.2 = p(a ∩ b)/0.5 . . . . . . . . fill in the given values
0.2*0.5 = 0.1 = p(a ∩ b)
p(a ∩ b) = 0.1
Answer:
1) The perpendicular bisector of the given line segment is 90 degrees
Step-by-step explanation:
I don't know the second one
Answer is B. Becuz (4,096)1/3 equals to 16. And so does (16×16)1/2
Answer:
10/25 or in percentage it is 40%
Step-by-step explanation:
