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4 years ago

10

Brandon has 32 stamps. He wants to display the stamps in rows, with the same number of stamps in each row. How many different wa

ys can he display the stamps? Explain.

1 answer:

Leokris [45]4 years ago

4 0

If you divide 32 by 4 you get 8

so, one way he can display them is 4 by 8

Like this,

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3 years ago

What is 80 percent of 60. write and solve a proportion. thank you

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3 years ago

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How do you write 4 hundredths,3 tenths, and 6 ones as a decimal?

Vsevolod [243]

The answer should be 6.34. This is because since the 6 is in the ones place, it should be the whole number. The 3 is a tenths so it should be the first number after the decimal. Finally, since 4 is in the hundredths place, it should be two places from the whole number.

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3 years ago

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6n-3>-18<br> Solve the inequality

Tamiku [17]

Answer:

<h3>n>-5/2</h3>

Step-by-step explanation:

First, you have to isolate it on one side of the equation. Remember that, isolate n on one side of the equation.

6n-3>-18

6n-3+3>-18+3 (Add 3 from both sides.)

-18+3 (Solve.)

-18+3=-15

6n>-15

6n/6>-15/6 (Divide by 6 from both sides.)

-15/6 (Solve.)

-15/6=-5/2

n>-5/2

In conclusion, the correct answer is n>-5/2.

3 0

3 years ago

]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf

Anna35 [415]

Answer:

$\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

Step-by-step explanation:

Circumference of circle = $\pi \cdot d$

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to $\frac{360^{\circ}}{n^{\circ}}$

So, Number of sectors = $\frac{360^{\circ}}{n^{\circ}}$

The arc length of each sector is the circumference divided by the number of sectors

$\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}$

Diameter d = 2r (r = radius)

$\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$

Option b is true

Hence $\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

7 0

4 years ago